Question

2. Complete the Table 4.1 on the basis of Information available in the symbols
given below
(a), 35c
(b)
12
12 C
(C)
85 Br
81
35
Table 4.1
Element
n
n​

Answer 1

The table can be completed as follows:-

 Element CICBrnp17635nn18646

np of Cl= Atomic number =17

nn of Cl= Mass number - Atomic number =A−Z=35−17=18np of C= Atomic number =6nn of C= Mass number - Atomic number =A−Z=12−6=6np of Br= Atomic number =35nn of Br= Mass number - Atomic number =A−Z=81−35=46