Question

2. Compute the heat generated while transferring 96000 coulomb of charge in one hour through a potential difference of 50 V.

Answer 1

Answer:

Given parameters

• Charge (Q) = 96000 C

• Time (t) = 1hr = 60 x 60 = 3600 s

• Potential difference (V) = 50 V

Let us calculate current (I)

• I = Q/t

I = (96000)/(3600)

I = (80/3) A

Let us calculate the quantity of heat generated by using the formula

• H = V × I × t

H = 50 × (80/3) × 3600

$H = 4.8 × 10^6 J$

$\huge{\therefore{ \color{lime} \tt{the \: heat \: generated \: is \: 4.8 x 10^6 J.} }}$

Answer 2

GIVEN:

• Charge (Q) = 96000 C
• Time taken (t) = 1 hour
• Potential difference (V) = 50 V

TO FIND:

• Heat energy (H)

SOLUTION:

Using the formula,

• Current (I) = Q/T

Where,

• Q = 96000 C
• T = 1 hour
• T = 60 × 60 sec
• T = 3600 sec

Substituting we get,

• I = 96000/3600
• I = 960/36
• I = 80/3 A

Using the formula,

• Heat (H) = VIT

Where,

• V = Potential difference
• I = Electric current
• T = Time taken

Substituting we get,

• H = 50 × 80/3 × 3600
• H = 50 × 96000
• H = 4800000
• H = 4.8 × 10⁶ J

ANSWER:

• Heat energy generated is 4.8 × 10⁶ J.

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