Question

2. Compute the zeroes of the polynomial x^2-5x +6. Also establish a relationship
between the zeroes and coefficients.​

Answer 1

Step-by-step explanation:

x^2 - 5x + 6

x^2 - 2x - 3x + 6. (6= 2×3)

x(x - 2) - 3(x - 2)

(x -2)(x -3) =0

therefore, x -2 = 0 and x - 3 = 0

x= 2 and x =3

sum of zeroes = - (coefficient of x ) / ( coefficient of x^2)

2+3 = - ( - 5)/ 1

5 = 5

products of zeroes = constant term / coefficient of x^2

2×3 = 6 / 1

6 = 6