Question

2. Consider a heater rated with 2640 Watt (2 pts.)
a) What is the energy (in KWh) it consumes when operating continuously during one day?
b) Find the source voltage to which the heater is connected to, if the current drawn is 12A.

Answer 1

Answer:

a) 63KWH

b) 220V

Explanation:

a)

Q = P.T

1 day: 24H

2640W to KW = 2640/1000

Q = (2640*10^-3)KW * 24H

Q = 63.36KWH or 63KWH to 2 significant figures (preferred here)

b)

P = VI

2640W = V * 12

V = 2640/12

V = 220 V (p.d)

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