Question

(2) Consider the A P. 4, 11, 18, 25, 32, ... The term 1, in this
A. P. is 308. Find n.​

Answer 1

Given:-

• A P. 4, 11, 18, 25, 32

To find:-

• n of 308 in this AP

Solution:-

• First term of AP is 4
• common difference of AP is 7

1. 11-4=7
2. 18-11=7

now find n of 308

a(n)=a+(n-1)d

put value

308=4+(n-1)7

308-4=(n-1)7

308-4=(n-1)7

304/7=(n-1)

43.42=n-1

44.42=n

hence ,308 is not in this AP

Note :- Its not 308 its 368

a(n)=a+(n-1)d

368=4+(n-1)7

368-4=(n-1)7

364=(n-1)7

52=(n-1)

52+1=n

53=n[Answer]