Question

2. Consider the following frequency
distribution of the heights of 60 students
of a class
Height (in cm) No. of Students
150-155
15
155-160
13
160-165
10
165-170
8
170-175
9
175-180
5
The upper limit of the median class in the
given data is :
(a) 165 (b) 160 (c) 155 (d) 170​

Answer 1

Answer:

Answer-

Side of square = 18cm

Area of square path = 18cm×18cm = 324cm²

Side of tile = 3cm

Area of one tile = 3cm × 3cm = 9cm²

number of tiles can be laid =

= \frac{area \: of \: path}{area \: of \: tile}=

areaoftile

areaofpath

= 324 cm / 9cm

= 36

36 tiles can be laid