Question

2. Construct a A ABC in which base BC = 4.5 cm, B = 45° and AB + BC = 8.5 cm.​

Answer 1

Construct a line BC = 4.5 cm

Construct ∠CBX = 45°

From BX, cut the line segment BD which is equal to AB + AC = 8 cm

Join the points

CD Construct a perpendicular bisector of CD which meets BD at the point A

In order to obtain the required triangle ABC join CA

ATTACHMENT

We know that A lies on CD which is the perpendicular bisector

So we get AC = AD

We know that BD = 8cm

It can be written as BA + AD = 8cm

So we get AB + AC = 8cm

Therefore, △ ABC is the required triangle.