Question

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Construct A APQR, given that QR = 3 cm, .PQR = 45° and
QP - PR =2 cm.​

Answer 1

Answer:

• To construct ΔPQR, use the following steps.
• Draw the base QR of length 3 cm.
• Make an angle XQR = 45° at point Q of base QR.
• Cut the line segment QS =QP- PR = 2 cm from the ray QX.
• Join SR and draw the perpendicular bisector of SR say AB.
• Let bisector AB intersect QX at P. Join PR Thus, ΔPQR is the required triangle.

Step-by-step explanation:

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Answer 2

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