2. Construct a quadrilatercel
quadrilatercel ABCD in which
AB = 3.5 cm BC = 5cm, CD = 5.6 cm , DA =4 cm, and BD=5.4 I want appropriate steps and correct answer will be marked as brainliest.
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Steps of Construction:
(i) Construct a line segment AB = 3.5 cm.
(ii) Taking A as centre and 4 cm radius construct and arc and with B as centre and 5.4 cm construct an arc which meets the previous arc at the point D.
Now join AD and BD.
(iii) Taking B as centre and 5 cm radius, construct an arc
Taking D as centre and 5.6 cm radius, construct an arc which meets the previous arc at the point C.
(iv) Join BC and CD.
Hence, ABCD is the required quadrilateral.
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