Question

2. Construct a triangle in which:
a. BC = 6 cm, AC = 5.0 cm and angle C = 60°
b. XY = 5.2 cm, XZ = 6.5 cm and angle X = 75°
c. PQ = 6.2 cm, QR = 9.0 cm and angle Q = 30°​

Answer 1

Answer:

The ΔA

′

BC

′

whose sides are

4

3

of the corresponding sides of ΔABC can be drawn as follows:

Step 1: Draw a ΔABC with side BC=6cm,AB=5cm,∠ABC=60

∘

Step 2: Draw a ray BX making an acute angle with BC on the opposite side of vertex A.

Step 3: Locate 4 points, B

1

,B

2

,B

3

,B

4

on line segment BX.

Step 4: Join B

4

C and draw a line through B

3

, parallel to B

4

C intersecting BC at C

′

.

Step 5: Draw a line through C

′

parallel to AC intersecting AB at A

′

.

The triangle A

′

BC

′

is the required triangle.

Answer 2

Answer:

The ΔA′BC′ whose sides are 43 of the corresponding sides of ΔABC can be drawn as follows:

The ΔA′BC′ whose sides are 43 of the corresponding sides of ΔABC can be drawn as follows:Step 1: Draw a ΔABC with side BC=6cm,AB=5cm,∠ABC=60∘

The ΔA′BC′ whose sides are 43 of the corresponding sides of ΔABC can be drawn as follows:Step 1: Draw a ΔABC with side BC=6cm,AB=5cm,∠ABC=60∘Step 2: Draw a ray BX making an acute angle with BC on the opposite side of vertex A.

The ΔA′BC′ whose sides are 43 of the corresponding sides of ΔABC can be drawn as follows:Step 1: Draw a ΔABC with side BC=6cm,AB=5cm,∠ABC=60∘Step 2: Draw a ray BX making an acute angle with BC on the opposite side of vertex A.Step 3: Locate 4 points, B1,B2,B3,B4 on line segment BX.

The ΔA′BC′ whose sides are 43 of the corresponding sides of ΔABC can be drawn as follows:Step 1: Draw a ΔABC with side BC=6cm,AB=5cm,∠ABC=60∘Step 2: Draw a ray BX making an acute angle with BC on the opposite side of vertex A.Step 3: Locate 4 points, B1,B2,B3,B4 on line segment BX.Step 4: Join B4C and draw a line through B3, parallel to B4C intersecting BC at C′.

The ΔA′BC′ whose sides are 43 of the corresponding sides of ΔABC can be drawn as follows:Step 1: Draw a ΔABC with side BC=6cm,AB=5cm,∠ABC=60∘Step 2: Draw a ray BX making an acute angle with BC on the opposite side of vertex A.Step 3: Locate 4 points, B1,B2,B3,B4 on line segment BX.Step 4: Join B4C and draw a line through B3, parallel to B4C intersecting BC at C′.Step 5: Draw a line through C′ parallel to AC intersecting AB at A′.

The ΔA′BC′ whose sides are 43 of the corresponding sides of ΔABC can be drawn as follows:Step 1: Draw a ΔABC with side BC=6cm,AB=5cm,∠ABC=60∘Step 2: Draw a ray BX making an acute angle with BC on the opposite side of vertex A.Step 3: Locate 4 points, B1,B2,B3,B4 on line segment BX.Step 4: Join B4C and draw a line through B3, parallel to B4C intersecting BC at C′.Step 5: Draw a line through C′ parallel to AC intersecting AB at A′.The triangle A′BC′ is the required triangle.

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