Question

2. Construct ∆ABC such that CB = 100°, BC = 6.4 cm, angal C 50° and construct its in circle ​

Answer 1

Answer:

$(i)Drawn BC = 6.4 cm </p><p>(ii)∠B=100∘ and ∠C=50∘ using the protector. Where the rays YB and XC meet, name the point as A </p><p>△ABC is thus obtained </p><p>(iii) Construct the angle bisectors of∠B and ∠C and let them meet at point O. </p><p> (iv) Through point O, draw a perpendicular to line. Let the perpendicular meet the line at point P. </p><p>(v) With O as centre and OP as radius , draw a circle inside the △ABC.</p><p>This is the required incircle.</p><p></p><p>$