Question

- 2) Construct ∆DEF such that DE = EF = 6 cm ∆F = 45° and construct its circumcircle​

Answer 1

Answer:

This circle is thus required circumcircle.

Step-by-step explanation:

Solution

(i) Draw a line EF=6 cm.

(ii) With F as centre , draw an angle of 45

∘

using the protractor

(iii) With E as centre and 6 cm as radius , cut an arc on ray FX and name its as D

(iv)Join DE. △DEF is thus obtained

(v)Draw the perpendicular bisectors of the lines DF and EF Let these perpendicular bisector meet at point O

(vi)With O as centre and OE as radius , construct a circle touching all the vertices of the △DEF

This circle is thus required circumcircle

.

Answer 2

Answer:

DE = EF

< DFE = < EDF = 45°

< DEF = 90°

Steps of construction :

(i) Draw a line EF=6 cm.

(ii) With F as centre , draw an angle of 45∘ using the protractor 

(iii) With E as centre and 6 cm as radius , cut an arc on ray FX and name its as D 

(iv)Join DE. △DEF  is thus obtained 

(v)Draw the perpendicular bisectors of the lines DF and EF Let these perpendicular bisector meet at point O

(vi)With O as centre and OE as radius , construct a circle touching all the vertices of the △DEF