2 copper wires a and b of length 30 m and 10 m have radii 2 cm and 1 cm respectively compare the resistance of 2 wires
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because the material is same so specific resistance(ρ) will be same.
given l₁=30m l₂=10m
r₁=2cm =0.02m r₂=1cm =0.01m
R₁/R₂ =l₁A₂/l₂A₁
=30*Π(0.01)^2/10*Π(0.02)^2
=3/4
R₁/R₂ =3/4
given l₁=30m l₂=10m
r₁=2cm =0.02m r₂=1cm =0.01m
R₁/R₂ =l₁A₂/l₂A₁
=30*Π(0.01)^2/10*Π(0.02)^2
=3/4
R₁/R₂ =3/4
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