2 cos-1 x = cos-1 (2x2 -1)
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To prove--->
2Cos⁻¹x = Cos⁻¹ ( 2x² - 1 )
Proof---> Let, Cos⁻¹x = θ
=> x = Cosθ
Now we know that,
Cos2θ = 2Cos²θ - 1
=> Cos2θ = 2 ( Cosθ )² - 1
Putting Cοsθ = x , we get,
=> Cos2θ = 2 ( x )² - 1
=> Cos2θ = 2x² - 1
Taking cos⁻¹ both sides , we get,
=> Cos⁻¹ ( Cos2θ ) = Cos⁻¹ ( 2x² - 1 )
=> 2θ = Cos⁻¹ ( 2x² - 1 )
Putting θ = Cos⁻¹x , we get,
=> 2 Cos⁻¹ x = Cos⁻¹ ( 2x² - 1 )
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