Math, asked by karan5677saini, 7 months ago

2(cos^2 45 + tan^2 60)-6(sin45-tan^2 30)=6​

Answers

Answered by sandy1816
1

Step-by-step explanation:

2(cos²45+tan²60)-6(sin²45-tan²30)

=2(1/2+3)-6(1/2-1/3)

=2(1+6/2)-6(3-2/6)

=2(7/2)-6(1/6)

=7-1

=6

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