Question

2 cos 2 A = root 3. find sin 3 A​

Answer 1

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Answer 2

$\huge\star{\mathfrak{\underline{\red{Answer}}}}$

◖ Step by step Explanation:-

$\large\tt\implies\ 2cos \: 2A \: = \: \sqrt{3}$

$\large\tt\implies\ cos2A \: = \: \frac{\sqrt{3} }{2}$

❖According to trigonometric ratios ; the value becomes cos30° ; consitute it in solution;

$\large\tt\implies\ cos2A \: = \: cos30$

❖Multiply by $\tt\frac{3}{2}$ both left and right side;

$\large\tt\implies\frac{3}{2} \times\ 2a \: = \: 30 \times\frac{3}{2}$

❖Cancelling the values ;

$\large\tt\implies\ 3a \: = \: 45°$

❖Take sin both side ;

$\large\tt\implies\ sin3A \: = \: sin45°$

$\large\tt\implies\ sin3A \: = \: \frac{1}{\sqrt{2} }$