Question

(2 cos 2A-1)( tan 3A -1) = 0,find all possible values of A
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Answer 1

Step-by-step explanation:

Case 1:

2cos2A-1=0

2cos2A=1

cos2A=1/2

cos2A=cos60°

2A=60°

A=30°

Case2:

tan3A-1=0

tan3A=1

tan3A=tan45°

3A=45°

A=15°

Therefore,possible values of A=60° and 15°