Question

2 cos^2xsinx-2=0
find x​

Answer 1

Let sinx = X

cos²x = 1 - sin²x = 1 - X

So, the equation becomes,

2 (1 - X) (X) = 0

2X - 2X² = 0

X² - X = 0

X (X - 1) = 0

X = 0 or X = 1

sinx = 0 or sinx = 1

x = nπ or x = (4n+1)π/2