Math, asked by thaanisis12, 11 months ago

2 cos^3 theta-cos theta/sin theta-2 sin 3^thetha = cot theta

Answers

Answered by Anonymous
4

Step-by-step explanation:

2Cos³O - CosO / SinO - 2Sin³O

CosO(2Cos²O - 1)/SinO(1 - 2Sin²O)

CosO*Cos2O / SinO*Cos2O

CosO/SinO = CotO

Similar questions