Question

2 ( cos^4 60^0 + sin^4 30^0 ) - (tan^2 60^0 + cot^2 45 ^ 0 )
pls tell​

Answer 1

Answer:

$2 \times ( {(cos60)}^{4} + {(sin30)}^{4} ) - ( {(tan60)}^{2} + {(cot45)}^{2} ) =$

$2 \times ( {( \frac{1}{2} )}^{4} + {( \frac{1}{2} )}^{4} ) - ( { \sqrt{3} }^{2} + {1}^{2} ) =$

$2 \times \frac{1}{8} - 4 = \frac{1}{4} - 4 = - \frac{15}{4}$

Ans