Question

2(cos? 45° + tan? 60°) - 6(sin? 45° - tan 30°)​

Answer 1

Answer:

$2( \frac{ \sqrt{3} }{2} + \sqrt{3}) - 6( \frac{ \sqrt{3} }{2} - \frac{1}{ \sqrt{3} } ) \\ = 2( \frac{ \sqrt{3} + 2 \sqrt{3} }{2} ) - 6( \frac{3 - 2}{2 \sqrt{3} } ) \\ = \sqrt{3} + 2 \sqrt{3} - \frac{6}{2 \sqrt{3} } \\ \\ = \frac{6 + 12 - 6}{2 \sqrt{3} } \\ = \frac{12}{2 \sqrt{3} } \\ = \frac{6}{ \sqrt{3} } \: \: \: \: \\ \: \: \: \: or \frac{2}{3}$

hope its help full