Math, asked by bhushanghonge8, 9 months ago

2(cos? 45° + tan? 60°) - 6(sin? 45° - tan 30°)​

Answers

Answered by abhijitpanja366
0

Answer:

2( \frac{ \sqrt{3} }{2}  +  \sqrt{3}) - 6( \frac{ \sqrt{3} }{2}   -  \frac{1}{ \sqrt{3} } ) \\  = 2( \frac{ \sqrt{3}  + 2 \sqrt{3} }{2}  ) - 6( \frac{3 - 2}{2 \sqrt{3} } ) \\  =  \sqrt{3}  + 2 \sqrt{3}  -  \frac{6}{2 \sqrt{3} }  \\   \\  =  \frac{6 + 12 - 6}{2 \sqrt{3} }  \\  =  \frac{12}{2 \sqrt{3} }  \\  = \frac{6}{ \sqrt{3} }  \:  \:  \:  \:  \\  \:  \:  \:  \: or \frac{2}{3}

hope its help full

Similar questions