Question

2 cos(A-B) = 2 sin(A+B)=root 3, find angles A and B.

Answer 1

Step-by-step explanation:

2COS(A-B)=

$\sqrt{3}$

COS(A-B)=

$\sqrt{3} \div 2$

A-B=30,

2SIN(A-B)=

$\sqrt{3}$

SIN(A+B)=

$\sqrt{3} \div 2$

A+B=60

solve A-B=30,

A+B=60

we get,

A=45,

B=15

Answer 2

Step-by-step explanation:

therefore A =45 and B =15.