2 cos squared theta + 3 sin theta - 3 = 0 determine the value of theta..
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soory don't know the ans
Answered by
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Answer:
2cos^2thita+3sinthita-3=0
2(1-sin^2thita)+3sinthita-3=0
2-2sin^2thita+3sinthita-3=0
let sinthita=x
2x^2-3x+1=0
2x^2-2x-x+1=0
2x(x-1)-1(x-1)=0
(2x-1)(x-1)=0
either 2x-1=0
x=1/2
so sinthita=1/2
thita =30
or x-1=0
x=1
sinthita=1
thita =90
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