Question

2 cos theta-sin theta=1/√2. then find the value of 2sin theta+cos theta​

Answer 1

Answer:

mc020

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

IT WILL BE DIFFICULT TO SOLVE THE EQUATION, EASIEST WAY IS TO PUT THE VALUE OF ∅ ONE BY ONE.

We know that cos45°= 1/√2

and  sin45°= 1/√2

eq.       2cos∅ - sin∅ = 1/√2

let's subsitute the value of ∅ by 45°

i.e.     2cos45°- sin45° = 1/√2

i.e.       2×1/√2- 1/√2=   2-1/√2  =  1/√2

 hence 45° satisfies the condition

then,   2sin∅ + cos∅

=  2×sin45° + cos 45°

=  2×1/√2 +  1/√2

=  2+1/√2

=  3/√2

option 3 is the correct answer = 3/√2

Hope it will help.

All the best