2 cos² theta minus cos theta = 0
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Answered by
0
Answer:
Use the identity
cos
2β=1−2sin2β .
1−2sin2θ+cosθ=0
1−2(1−cos2θ)+cosθ=0
1−2+2cos2θ+cosθ=0
2cos2θ+cosθ−1=0
2cos2θ+2cosθ−cosθ−1=0
2cosθ(cosθ+1)−(cosθ+1)=0
(2cosθ−1)(cosθ+1)=0
θ=π3+2πn,2π3+2πn,π+2πn
.
Hopefully this helps!
Answered by
0
Answer:
cos theta = 1/2
Step-by-step explanation:
take cos theta common from both the terms.
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