Math, asked by monikbagadia, 6 months ago

2 cos² theta minus cos theta = 0​

Answers

Answered by gaurvidixit1310
0

Answer:

Use the identity

cos

2β=1−2sin2β .

1−2sin2θ+cosθ=0

1−2(1−cos2θ)+cosθ=0

1−2+2cos2θ+cosθ=0

2cos2θ+cosθ−1=0

2cos2θ+2cosθ−cosθ−1=0

2cosθ(cosθ+1)−(cosθ+1)=0

(2cosθ−1)(cosθ+1)=0

θ=π3+2πn,2π3+2πn,π+2πn

.

Hopefully this helps!

Answered by bhumikabv2004
0

Answer:

cos theta = 1/2

Step-by-step explanation:

take cos theta common from both the terms.

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