Question

2(cos⁴60+sin⁴30)-(tan²60-cot²45)3sec²30=9/4​

Answer 1

Step-by-step explanation:

we know

cos60 = 1/2

sin 30 =1/2

tan60 = √3

cot45 = 1

sec30 = 2/√3

2[(1/2)^4+(1/2)^4]-[( √3)^2-(1)^2)]3x(2/ √3)^2

2[1/16+1/16]-[3-1]3x4/3

(2x1/8)-8

1/4-8

-7.75