Math, asked by ashwatiunair9465, 1 year ago

2(cos58/sin32) -√3(cos38*sec52/tan15*tan60*tan75)

Answers

Answered by harshitha100
3
2(cos58/sin32)-√3(cos38*sec52/tan15*tan60*tan75)
=2(cos (90-32)/sin32)-√3(cos38*1/cos52/tan15*√3*1/tan15
=2-1
=1

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