2 cos65÷sin25 - tan20÷cot70 - since +tan5×tan85
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2xcos(90-25)÷sin25-tan(90-70)÷cot70-tan(90-5)×1/cot85
2xsin25÷sin25-cot70÷cot70-cot85x1/cot85
2x1-1-1
2-2=0
therefore answer is 0
2xsin25÷sin25-cot70÷cot70-cot85x1/cot85
2x1-1-1
2-2=0
therefore answer is 0
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