Math, asked by smurfacc605, 19 days ago

2(cos65°/sin25°)-sec²54°-cot²36°/cosec²57°-tan²33° + cos0°+tan9°+tan12°+tan78°+tan81°​

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Answered by yashshukla0608
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Step-by-step explanation:

2(cos65°/sin25°)-sec²54°-cot²36°/cosec²57°-tan²33° + cos0°+tan9°+tan12°+tan78°+tan81°

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