Question

√2(cos7π/4+isin7π/4) express in x+iy​

Answer 1

Step-by-step explanation:

Let the given complex number in polar form be z

$z = \sqrt{2} ( \cos( \frac{7\pi}{4}) + i\sin( \frac{7\pi}{4} ))$

$= > z = \sqrt{2} ( \cos(2\pi - \frac{\pi}{4} ) + i \sin(2\pi - \frac{\pi}{4} ) )$

$= > z = \sqrt{2} ( \cos( \frac{\pi}{4} ) - i \sin( \frac{\pi}{4} ) )$

$= > z = \sqrt{2} ( \frac{1}{ \sqrt{2} } - i \frac{1}{ \sqrt{2} } )$

$= > z = 1 - i$

Answer 2

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