Question

2 cosec 2A + cosec A = sec A * cot A/ 2​

Answer 1

Answer:

LHS:

=sec²A+cosec²A

=(1+tan²A)+(1+cot²A)

[USING sec²A=1+tan²A and cosec²A=1+cot²A]

=1+tan²A+1+cot²A

=tan²A+cot²A+2

=RHS

Hence, proved

Hope this helps you

Answer 2

Answer:

To Prove:

−cosec A +2 cosec 2A = sec A cot A2LH

Scosec A +2 cosec 2A=1sin A+2sin 2A=1sin A+22 sin A cos A    

(since sin 2x = 2 sin x cos x)=cos A + 1sin A cos A=2 cos2A22 sinA2cosA2cos A        

  (Since 1 + cos 2x =2 cos2x)=cosA2sinA2cos A=sec A cot A2=RHS

Hence Proved.

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