Question

2(cosec 30 )^2 +(sin60)^2 - 3/4(tan30)^2 = 10

Answer 1

Answer:

$2 \times {2}^{2} + ({ \frac{ \sqrt{3} }{2} })^{2} - \frac{3}{4} \times ({ \frac{1}{ \sqrt{3} } })^{2}$

$2 \times 4 + \frac{3}{4} - \frac{3}{4} \times \frac{1}{3}$

$8 + 0 \times \frac{1}{3} = 8$

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