Question

2. cosec A tan A= sec A​

Answer 1

Answer:

SecA = 1/cos A.....✔✔✔

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Answer 2

$LHS \\\\ = cosecA \ tanA \\ \\ = \frac{1}{sinA} \times \frac{sinA}{cosA} \\\\ = \frac{1}{cosA} \\\\ =secA =RHS \\\\ -------------- \\ tan\theta=\frac{sin\theta}{cos\theta} \\\\ cosec\theta=\frac{1}{sin\theta} \\\\ sec\theta=\frac{1}{cos\theta} \\ --------$

hope it helps..!