2 cosec square (60) +3 cos (45) - sin square (30) tan square (60)
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Determine the value of x, such that 2cosec
2
30
0
+xsin
2
60
0
−
4
3
tan
2
30
0
=10.
Easy
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2cosec
2
30
∘
+xsin
2
60
∘
−
4
3
tan
2
30
∘
=10
L.H.S:2(2)
2
+x(
2
3
)
2
−
4
3
(
3
1
)
2
=10 [∵cosec30
∘
=2,sin60
∘
=
2
3
,tan30
∘
=
3
1
]
⇒8+
4
3x
−
4×3
3
=10
⇒8+
4
3x
−
4
1
=10
⇒
4
32+3x−1
=10
⇒3x+31=40
⇒3x=40−31
⇒3x=9
⇒x=
3
9
⇒x=3
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