Question

2 cube each of volume 64cm^2 are joined end find the surface area of the resultin​

Answer 1

Step-by-step explanation:

⇒Volume of cubes = 64 cm

3

⇒(Edge)

3

=64

⇒Edge =4 cm

If cubes are joined end to end, the dimensions of the resulting cuboid will be

4 cm, 4 cm, 8 cm.

Surface area of cuboids =2(lb+bh+lh)

=2(4×4+4×8+4×8)

=2(16+32+32)

=2(16+64)

=2(80)=160 cm

2

solution

Answer 2

Answer:

• Total surface area of cuboid = 160 cm²

Step-by-step explanation:

Given:

• Two cube each of volume = 64 cm³

To Find:

• Surface area of resulting cuboid.

Now, we know that,

⇒ Volume of cube = a³

⇒ 64 = a³

⇒ a = ∛64

⇒ a = 4 cm

Now, we know that, if two cubes are joined then,

⇒ Length of cuboid = side of cube + side of cube

⇒ Length of cuboid = 4 + 4 = 8 cm

$\rule{200}{2}$

⇒ Breadth of cuboid = side of cube = 4 cm

$\rule{200}{2}$

⇒ Height of cuboid = side of cube = 4 cm

$\rule{200}{2}$

Now, we know that,

⇒ Total surface area of cuboid = 2(lb + bh + hl)

⇒ Total surface area of cuboid = 2(8 × 4 + 4 × 4 + 4 × 8)

⇒ Total surface area of cuboid = 2(32 + 16 + 32)

⇒ Total surface area of cuboid = 2(80)

⇒ Total surface area of cuboid = 160 cm²

Hence, Total surface area of cuboid = 160 cm²