2 cubes each of volume 64 cm^3 are join end to end find the surface area of exerting 2 cuboid
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Given Volume of both cubes = 64cm^3
find one side = (64)^1/3 = 4
The cubes are joined end to end
Length = 8cm
width = 4cm
height= 4 cm
Surface area,
2(lb+bh+hl)
2(32+16+32)
160 cm^2
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find one side = (64)^1/3 = 4
The cubes are joined end to end
Length = 8cm
width = 4cm
height= 4 cm
Surface area,
2(lb+bh+hl)
2(32+16+32)
160 cm^2
Glad to help u
Follow me dude plz
Anonymous:
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Answered by
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Answer: 160cm².
Step by step explanation:
Given,
Volume of both cubes = 64cm³
Volume of one cube =a³
⇒ 64 = a³
⇒ (4) = a³
⇒ a=4
To find: We have to find the Surface area of resulting cuboids.
We know that, when two cubes are joined they form cuboid:
Length of cuboid=4+4= 8cm
Breadth of cuboid= 4cm
Height of cuboid= 4cm
Surface area of cuboid = 2(lb+bh+lh)
2(8×4+4×4+4×8)
= 2(32+16+32)
= 2(80)
= 160cm²
Therefore, Surface area of Cuboid is 160 cm².
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