2 cubes each of volume 64 cm are joined end to end find the surface area of the resulting cuboid?
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volume of cube =64 cm
side =cube root of 64
= 4 cm
side of another cube =4 as well
New length = 4+4=8
breath 4 cm
height 4cm
Surface area of cuboid =2 (lb +bh+lh)
2(8*4+4*4+8*4)
2 (32+16+32)
2 *80
160cm square
side =cube root of 64
= 4 cm
side of another cube =4 as well
New length = 4+4=8
breath 4 cm
height 4cm
Surface area of cuboid =2 (lb +bh+lh)
2(8*4+4*4+8*4)
2 (32+16+32)
2 *80
160cm square
yashveeryadav:
sir 4 intoo 4 16 hota hai so total surface area is come 160
slight silly mistake
thanks brother
its ok sir
Answered by
2
Answer: 160cm².
Step by step explanation:
Given,
Volume of both cubes = 64cm³
Volume of one cube =a^3
⇒ 64 = a³
⇒ (4) = a³
⇒ a=4
We know that, when two cubes are joined they form cuboid.
Length of cuboid=4+4= 8cm
Breadth of cuboid= 4cm
Height of cuboid= 4cm
Surface area of cuboid=2(lb+bh+lh)
2(8×4+4×4+4×8)
= 2(32+16+32)
= 2(80)
= 160cm²
Therefore, Surface area of Cuboid is 160 cm².
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