Question

2 cubes each of volume 64 CM square are joined end to end find the surface area of the resulting cuboid. ​

Answer 1

Given:

⇒Volume of cubes = 64 cm³

⇒(Edge)³ =64

⇒Edge =4 cm

If cubes are joined end to end, the dimensions of the resulting cuboid will be

4 cm, 4 cm, 8 cm.

Surface area of cuboids =2(lb+bh+lh)

$\sf = 2(4 \times 4 + 4 \times 8 + 4 \times 8)$

$\sf \: = 2(16 + 32 + 32)$

$\sf = 2(16 + 64)$

$\sf = 2(80) \color{purple} = {160cm}^{2}$

Answer 2

Answer:

160 cm² is the surface area of the cuboid.

Step-by-step explanation:

Given :-

• 2 cubes each of volume 64 cm³ are joined end to end and took a shape as a cuboid.

To find :-

• The total surface area of the resulting cuboid.

Solution :-

Volume = 64 cm³

a³ = 64

64  = 4 × 4 × 4

a = 4 cm

A cube has all sides equal when the breadths of two cubes are added, 4 becomes double, which is 8, and the length and height will be 4 only.

New dimensions of the cuboid are :

Length = 4 cm

Breadth = 8 cm

Height = 4 cm

Total surface area of cuboid :

2(lb + bh + hl)

2[(4×8) + (8×4) + (4×4)]

2[(32) + (32) + (16)]

2[80]

160

∴ Surface area of the resulting cuboid is 160 cm².