Question

2 cubes each of volume 64 cm³ are joined end to end. Find the surface area of the resulting cuboid.​

Answer 1

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The diagram is given as:

• Refer to the above attachment.

Given:

• The Volume (V) of each cube is = 64 cm3

This implies that a³ = 64 cm³

Therefore, a = 4 cm

Now,

• The side of the cube = a = 4 cm

Also, the length and breadth of the resulting cuboid will be 4 cm each. While its height will be 8 cm.

So, the surface area of the cuboid = 2(lb + bh + lh)

= 2(8×4 + 4×4 + 4×8) cm²

= 2(32 + 16 + 32) cm²

= (2 × 80) cm²

= 160 cm²

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Answer 2

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The Volume (V) of each cube is = 64 cm^3

This implies that a3 = 64 cm^3

∴ The side of the cube, i.e. a = 4 cm

Also, the breadth and length of the resulting cuboid will be 4 cm each while its height will be 8 cm.

So, the surface area of the cuboid (TSA) = 2(lb + bh + lh)

Now, by putting the values, we get,

= 2(8×4 + 4×4 + 4×8) cm^2

= (2 × 80) cm√2

Hence, TSA of the cuboid = 160 cm^2

Hope it's Helpful.....:)