Question

2 cubes each of volume 64 cm3 are joined end to end. Find the surface area of the resulting cuboid.​

Answer 1

Step-by-step explanation:

let the side of each cube = a

then a³=64

a=4

now the cuboid formed has

l as 8

b as 4

h as 4

tsa of cuboid = 2(lh+lb+bh)

2(16+32+32)

2(80)

160cm²

Answer 2

Given :

• 2 cubes each of volume 64 cm³ are joined end to end.

To Find :

• The surface area of the resulting cuboid = ?

Solution :

• It is given that, Volume of 1 cube is 64 cm³ and first we have to find the each side of the cube :

Finding the side of the cube

→ Volume of 1 cube = 64 cm³

→ volume of cube = (Side)³

→ 64 cm³ = (Side)³

→ ∛64 = Side

→ 4 cm = Side

→ Side = 4 cm

• Hence, the each side of the cube is 4 cm.

When two cubes are joined together end to end, then the Length will be doubled :

Finding dimensions :

• Length = side + side = 4 + 4 = 8 cm
• Breadth = 4 cm
• Height = 4 cm

Let Length be 'l', Breadth be 'b' and height be 'h'.

Finding surface area of resulting cuboid :

⋗ TSA of cuboid = 2(lb + bh + hl)

⋗ TSA of cuboid = 2(8 × 4 + 4 × 4 + 4 × 8)

⋗ TSA of cuboid = 2(32 + 16 + 32)

⋗ TSA of cuboid = 2 × 80

⋗ TSA of cuboid = 160 cm²

• Hence,the surface area of the resulting cuboid is 160 cm².