2 cubes each of volume 64 cm3 are joined end to end. Find the surface area of the resulting cuboid.
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We've to use these basic mensuration formulae to solve this problem :
Vol.(cube) = s^3.S.A.(cuboid) = 2 ( lb + bh + hl ).
As vol.(cube) = 64 cm^3,
Side = 4 cm.
Now, these cubes are joined together,
one of the dimensions say length will be doubled. ( Which dimension will be doubled depends upon on which side cubes are joined but it won't affect our answer anyway.)
So, for the resultant cuboid,
l = 8 cm & b = h = 4 cm.
Surface area = 2 ( 32 + 16 + 32 )
= 2 * 80 = 160 cm^2.
Vol.(cube) = s^3.S.A.(cuboid) = 2 ( lb + bh + hl ).
As vol.(cube) = 64 cm^3,
Side = 4 cm.
Now, these cubes are joined together,
one of the dimensions say length will be doubled. ( Which dimension will be doubled depends upon on which side cubes are joined but it won't affect our answer anyway.)
So, for the resultant cuboid,
l = 8 cm & b = h = 4 cm.
Surface area = 2 ( 32 + 16 + 32 )
= 2 * 80 = 160 cm^2.
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