Math, asked by vishal732192, 3 months ago

2 cubes each of volume 64 cm3 are joined end to end. find the surface area of the resulting cuboid.​

Answers

Answered by LakshyaNeGi24
1

Answer:

 \sqrt[3]{64}  = side\: of \: square \\ 4 = side \: of \: square \\ volume \: of \: rectangle = 4 \times 4 \times 8 \\  = 128 {cm}^{3 }  \\ hope \: you \: can \: understand

Answered by EuphoricBunny
3

☘️ Given :

  • Volume of each cube = 64 cm³
  • Joined end to end

☘️To find:

  • Surface area of the resulting cuboid.

☘️ Solution:

First, we'll find sides of cube.

We know that,

Volume of cube = (side)³

→ 64 = (side)³

→ ³√64 = side

→ 4 = side

side = 4

Sides of cube are 4 cm.

C.S.A(Curved surface area) of cuboid = 2(lb + bh + hl)

  • length (l) = 4 + 4 = 8
  • breadth (b) = 4
  • height (h) = 4

C.S.A of cuboid = 2[(8)(4) + (4)(4) + (4)(8)]

C.S.A of cuboid = 2[32 + 16 + 32]

C.S.A of cuboid = 2(80)

C.S.A of cuboid = 160 cm²

☘️ Answer:

  • So the surface area of the resulting cuboid = 160 cm²
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