2 cubes each of volume 64 cm3 are joined end to end. find the surface area of the resulting cuboid.
Answers
Answered by
1
Answer:
Answered by
3
☘️ Given :
- Volume of each cube = 64 cm³
- Joined end to end
☘️To find:
- Surface area of the resulting cuboid.
☘️ Solution:
First, we'll find sides of cube.
We know that,
Volume of cube = (side)³
→ 64 = (side)³
→ ³√64 = side
→ 4 = side
→ side = 4
Sides of cube are 4 cm.
C.S.A(Curved surface area) of cuboid = 2(lb + bh + hl)
- length (l) = 4 + 4 = 8
- breadth (b) = 4
- height (h) = 4
C.S.A of cuboid = 2[(8)(4) + (4)(4) + (4)(8)]
C.S.A of cuboid = 2[32 + 16 + 32]
C.S.A of cuboid = 2(80)
C.S.A of cuboid = 160 cm²
☘️ Answer:
- So the surface area of the resulting cuboid = 160 cm²
Similar questions