Question

2 cubes each of volume 64 cm³are joined end to end .find the surface area of resulting cubiod

Answer 1

Volume of 1 cube=64 cm³

(side)³=64 cm³

a³=64 cm³

a³=4³

a=4

surface area of cuboid

length of cuboid=a+a=4+4=8 cm

Breadth=a=4 cm

height=a=4 cm

hence l=8 cm,b= 4 cm,h=4 cm

Area of cuboid=2(lb+bh+hl)

                        =2(8*4+4*4+4*8)

                       =2(32+16+32)

                      =2*80

                     =160 cm^2