Question

2 cubes each of volume 64cm^3 are joined end to end. Find the surface area of the resulting cuboid? ​

Answer 1

Answer:

The volume of cube 64 cm ^3

Side of cube  

3* root 64   =4 cm

Length of resulting cuboid 4+4=8

Surface area  

=2(lb+hl+bh)

=2(4(4)+4(8)+8(4))

=2(16+32+32)

=2(80)= 160 cm  ^2

 

Step-by-step explanation:

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Answer 2

$\large\sf{TSA\:of\:Cuboid=2(lb+bh+hl)}$

$\longrightarrow$$\large\sf{2(8×4+4×4+4×8)}$

$\longrightarrow$$\large\sf{2(32+16+32)}$

$\longrightarrow$$\large\sf{2(64+16)}$

$\longrightarrow$$\large\sf{2×80}$

$\longrightarrow$$\large\sf{{160cm}^{2}}$