2 cubes each of volume 64cm^3 are joined end to end .Find the surface area of the resulting cuboid?
Answers
Answered by
8
if one cuboid of volume is 64 raised to 3 and join the end the surface area of the resulting cuboid is as follows answer space Ti tubes two cubes each of the volume is 64 then 64 is divided by 2 and answer should be come of the solution of the simultaneous equation and hence our answer is complete thanks
Answered by
12
Heya !!!
here is your answer !!!
Volume of one cube => 64 cm² .
therefore side of one cube => a³
=> 64cm³ = a³
a => 4cm
now it is joined end to end ( two cubes )
=>
length will be => 8cm
Breath = 4cm
height = 4cm
hence , the surface area of cube =
=> 2 ( l * b + b * h + h *l )
=> 2 ( 8 * 4 + 4 *4 + 4 *8 ) cm²
=> 2 * 80 cm²
=> 160 cm²
hence , Total surface area Will be 160 cm²
hope it helps you dear !!!
thanks !!!
have a pleasant day !!!
☺☺
here is your answer !!!
Volume of one cube => 64 cm² .
therefore side of one cube => a³
=> 64cm³ = a³
a => 4cm
now it is joined end to end ( two cubes )
=>
length will be => 8cm
Breath = 4cm
height = 4cm
hence , the surface area of cube =
=> 2 ( l * b + b * h + h *l )
=> 2 ( 8 * 4 + 4 *4 + 4 *8 ) cm²
=> 2 * 80 cm²
=> 160 cm²
hence , Total surface area Will be 160 cm²
hope it helps you dear !!!
thanks !!!
have a pleasant day !!!
☺☺
Similar questions