Question

2 cubes each of volume 64cm3
are joined end to end. Find the surface area of
the resulting cuboids.

Answer 1

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length of cube =a

a^3 =64

⇒a=4

Length of cuboid = 8 = l

breadth of cuboid = 4=b

height of cuboid = 4=h

Surface area ⇒2(lb+bh+lh)

=2((8×4)+(4×4)+(8×4))

=2(32+16+32)

=160 cm^2

Answer 2

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⟼ Length of cube = a

a^3 =64

⇒a=4

➪Length of cuboid = 8 = l

➪breadth of cuboid = 4=b

➪height of cuboid = 4=h

Surface area $\sf{⇒2(lb+bh+lh)}$

=2((8×4)+(4×4)+(8×4))

=2(32+16+32)

=160 cm^2