Question

2 cubes each of volume 64m3 are joined end to end find the TSA of resulting cuboid ​

Answer 1

Answer:

Answer=160cm².

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Step-by-step explanation:

We've to use these basic mensuration formulae to solve this problem :

Vol.(cube) = s³

S.A.(cuboid) = 2 ( lb + bh + hl ).

As vol.(cube) = 64 cm³

Side = 4 cm.

Now, these cubes are joined together,

one of the dimensions say length will be doubled. ( Which dimension will be doubled depends upon on which side cubes are joined but it won't affect our answer anyway.)

So, for the resultant cuboid,

l = 8 cm & b = h = 4 cm.

Surface area = 2 ( 32 + 16 + 32 )

= 2 * 80 = 160 cm².

Answer 2

Answer:

TSA of cube is 96 m².

Step-by-step explanation:

Given :-

The lateral surface area of a cube is 64 m.

To find :-

Total surface area of cube.

Solution :-

Let the each side of cube be a m.

★Formula used :

${\boxed{\sf{CSA\:of\:cube=4a^2}}}$

CSAofcube=4a

2

According to the question,

4a² = 64

→ a² = 64/4

→ a² = 16

→ a = √16

→ a = 4

Each side of cube is 4 m.

★Formula used :

${\boxed{\sf{TSA\:of\:cube=6a^2}}}$

TSAofcube=6a

2

Total surface area of cube,

= 6a²

= 6×(4)² m²

= 6 × 16 m²

$\textbf{= 96 m²}$

Therefore, total surface area of cube is 96 m².