Question

2 cubes of each volume 64cm3 are joined end to end. Find the SURFACE AREA of the resulting cuboid.

Answer 1

= let the edge of cube = x cm

= volume of cube = x3

= 64 = x3

= 4 . 4 . 4 = x3

= x = 4 CM.

= length = 4+4 = 8cm

= breath = 4 cm

= height = 4 cm

= Surface area of resulting cuboid = 2(lb+bh+hl)

= 2(8 . 4 + 4 . 4 + 4 . 8)

= 2(32+16+32)

= 2(80)

= 160 cm2.

Answer 2

Answer: 160cm².

Step by step explanation:

Given,

Volume of both cubes = 64cm³

Volume of one cube =a³

⇒ 64 = a³

⇒ (4) = a³

⇒ a=4

We know that, when two cubes are joined they form cuboid:

Length of cuboid=4+4= 8cm

Breadth of cuboid= 4cm

Height of cuboid= 4cm

Surface area of cuboid = 2(lb+bh+lh)

2(8×4+4×4+4×8)

= 2(32+16+32)

= 2(80)

= 160cm²

Therefore, Surface area of Cuboid is 160 cm².