Question

2 cubes of volume 64 m^3 are joined end to end. Find the surface area of of the resulting cuboid.

Answer 1

HELLO DEAR,

VOLUME OF CUBE =(SIDE)²

THEN THE SIDE =

$\sqrt[3]{64} = 4m$

GIVEN JOIN END TO END


LENGTH OF NEW CUBOID = 8 cm,

HEIGHT = 4 cm,

WIDTH = 4 cm


$2(lb + lh + bh) \\ = > 2(8 \times 4 + 8 \times 4 + 4 \times 4) \\ = > 2 \times 80 = 160c {m}^{2}$



I HOPE ITS HELP YOU DEAR,
THANKS

Answer 2

8HEYA!!!!

Not copied one!!!!!

Given,

Volume of 2 cubes = 64m^3

volume of cube = (a)^3 or ( side)^3

ATP,

$= \sqrt[3]{64} \\ \\ = 16$

we know that when we join two cubes side by side it forms cuboid.

Hence, the length of cuboid = 2 × side of cube = 8 cm

breadth and width = 4cm respectively.

TSA of cuboid = 2 ( lb+bh+hl)

= 2 ( 8×4 + 4×4+4×8)

= 2 ( 32 + 16 + 32 )

= 2 ( 80 )

= 160cm ^ 2

HOPE THIS HELPS U. @MP #MAHABOOBPASHA #☺☺