Question

2. cutting a circle into equal section of a small central angle to find the area of circle:-
a) Theme
b) brief description
c) objective
d) Key words
e) material
f )procedure
g) conclusion
Write all the given above
please ans properly with correct answer I will mark it as brainlist​

Answer 1

Answer:

Here is a way to find the formula for the area of a circle:

circle 12 sectors

Cut a circle into equal sectors (12 in this example)

Divide just one of the sectors into two equal parts. We now have thirteen sectors – number them 1 to 13:

circle 13 including 2 half slices

Rearrange the 13 sectors like this:

sectors laid out like rectangle

Which resembles a rectangle:

sectors with rectangle on top

What are the (approximate) height and width of the rectangle?

The height is the circle's radius: just look at sectors 1 and 13 above. When they were in the circle they were "radius" high.

The width (actually one "bumpy" edge) is half of the curved parts around the circle ... in other words it is about half the circumference of the circle.

We know that:

Circumference = 2 × π × radius

And so the width is about:

Half the Circumference = π × radius

And so we have (approximately):

rectangle is (pi x radius) by radius radius

π × radius

Now we just multply the width by the height to find the area of the rectangle:

Area = (π × radius) × (radius)

= π × radius2

Note: The rectangle and the "bumpy edged shape" made by the sectors are not an exact match.

But we could get a better result if we divided the circle into 25 sectors (23 with an angle of 15° and 2 with an angle of 7.5°).

And the more we divided the circle up, the closer we get to being exactly right.

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

2. cutting a circle into equal section of a small central angle to find the area of circle:-

a) Theme

b) brief description

c) objective

d) Key words

e) material

f )procedure

g) conclusion

Write all the given above

please ans properly with correct answer I will mark it as brainlist